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2)2V4><>ABV ?@> N@848G=C >A>1C, O:0 T CG0A=8:>< ?@>F54C@8 70:C?V2;V, 2=5A5=> 4> 48=>3> 45@602=>3> @5TAB@C >AV1, O:V 2G8=8;8 :>@C?FV9=V 01> ?>2 O70=V 7 :>@C?FVTN ?@02>?>@CH5==O; 3):5@V2=8:0 CG0A=8:0 ?@>F54C@8 70:C?V2;V, DV78G=C >A>1C, O:0 T CG0A=8:>< ?@>F54C@8 70:C?V2;V, 1C;> ?@8BO3=CB> 73V4=> V7 70:>=>< 4> 2V4?>2V40;L=>ABV 70 2G8=5==O :>@C?FV9=>3> ?@02>?>@CH5==O 01> ?@02>?>@CH5==O, ?>2 O70=>3> 7 :>@C?FVTN; 4)AC1 T:B 3>A?>40@N20==O (CG0A=8: ?@>F54C@8 70:C?V2;V) ?@>BO3>< >AB0==VE B@L>E @>:V2 ?@8BO3C202AO 4> 2V4?>2V40;L=>ABV 70 ?>@CH5==O, ?5@5410G5=5 ?C=:B>< 4 G0AB8=8 4@C3>W AB0BBV 6, ?C=:B>< 1 AB0BBV 50 0:>=C #:@0W=8  @> 70E8AB 5:>=><VG=>W :>=:C@5=FVW , C 283;O4V 2G8=5==O 0=B8:>=:C@5=B=8E C73>465=8E 4V9, I> AB>ACNBLAO A?>B2>@5==O @57C;LB0BV2 B5=45@V2; 5)DV78G=0 >A>10, O:0 T CG0A=8:>< ?@>F54C@8 70:C?V2;V, 1C;0 70AC465=0 70 :@8<V=0;L=5 ?@02>?>@CH5==O, 2G8=5=5 7 :>@8A;828E <>B82V2 (7>:@5<0, ?>2 O70=5 7 E010@=8FB2>< B0 2V4<820==O< :>HBV2), AC48<VABL 7 O:>W =5 7=OB> 01> =5 ?>30H5=> 2 CAB0=>2;5=><C 70:>=>< ?>@O4:C; 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V4 !"',: ____________ /_____________/ V4 #&/: ____________ /_____________/ ____________ /_____________/ @07>: "  #- ' " # ! 0 4>3>2>@>< 2V4 ___________________@>:C !__________________ ______________ 2023 @>:C &59 0:B ?@89><C-?5@540GV B>20@C (=040;V ?> B5:ABC  :B) A:;045=89 !B>@>=0<8 73V4=> 7 >3>2>@>< 2V4 __________ @>:C !________ (=040;V  >3>2V@) <V6: #&,  " #:@70;V7=8FO, 2 >A>1V______________________ __________________________________________________________ B0 2 >A>1V __________________________________________________________________, (40;V 70 B5:AB>< FL>3> :B0  >:C?5FL), 7 >4=VTW AB>@>=8 B0 !"',  ________________(=0720 ?V4?@8T<AB20, CAB0=>28, >@30=V70FVW), 2 >A>1V___________________(40;V 70 B5:AB>< FL>3> :B0  >AB0G0;L=8:) A:;0;8 B0 ?V4?8A0;8 F59 :B ?@> =0ABC?=5: V4?>2V4=> 4> C<>2 >3>2>@C 2V4 _________ @>:C !_________ >AB0G0;L=8: ?5@5402, 0 >:C?5FL ?@89=O2 B0:89 B>20@ 70 04@5A>N _____________________________________: ! 0720 B>20@C, <0@:0, B8?, <>45;L 48=8FO 28<V@C V;L:VABL&V=0 70 >48=8FN B>20@C 157  (3@=)030;L=0 AC<0 157  (3@=) 07><  20% 030;L=0 AC<0 7 : V4?8A0==O< FL>3> :B0 >AB0G0;L=8: B0 >:C?5FL ?V4B25@46CNBL D0:B >AB02:8 ">20@C =0 7030;L=C AC<C _____ 3@= (________________), 7 C@0EC20==O<  20%: ___________ 3@=. 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